-6b^2-25b-11=0

Solution for -6b^2-25b-11=0 equation:

-6b^2-25b-11=0

a = -6; b = -25; c = -11;
Δ = b2-4ac
Δ = -252-4·(-6)·(-11)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-19}{2*-6}=\frac{6}{-12}
=-1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+19}{2*-6}=\frac{44}{-12}
=-3+2/3
$